It's easier if you make a substitution, as you'll report to the formula you know
Because c is the period !and how does ?
Again, if you can't see it, let T=t'+c, you'd have f(T+c)=f(T), which is f((t'+c)+c)=f(t'+c)
Whatever you have, if you add c, it will give the same !
Hmmm I've been looking for an explanation... I think I found itWhy is it nonsense? What makes it false?
Can it possibly equal ?
Only if :
- c=0 (which is not possible otherwise it would not make sense for the periodicity)
- f is c/2 periodic. But as I explained for c), it's not possible.
Thus b) is false