hi evreyone, here is the q: Find the solutions of the equation sin θ = 1/2 if: (a) θ is in the interval [0, 2 pi ) (b) θ is any real number
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Originally Posted by mHadad hi evreyone, here is the q: Find the solutions of the equation sin θ = 1/2 if: (a) θ is in the interval [0, 2 pi ) (b) θ is any real number The solutions exist in the first and second quadrand because you are trying to find positive one. The one in the first quadrand is then one in the second quadrand is,
i have read in a solution for a q that sin θ = 2 has no solution, why?
Originally Posted by mHadad i have read in a solution for a q that sin θ = 2 has no solution, why? because
Originally Posted by Quick because Becuase, If you want to be cool you can write,
Originally Posted by ThePerfectHacker Becuase, If you want to be cool you can write,
Originally Posted by mHadad hi evreyone, here is the q: Find the solutions of the equation sin θ = 1/2 if: (a) θ is in the interval [0, 2 pi ) (b) θ is any real number If is a solution of then so is . So using the solutions given by ImPerfectHacker we have: , and comprise all the real solution. RonL
Originally Posted by Quick Wow, retard after a retard.
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