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Thread: Need help :)

  1. #1
    Newbie
    Joined
    Feb 2009
    Posts
    9

    Need help :)

    Please help me to prove this.


    $\displaystyle \frac{\sin x}{x+\tan x}=\frac{\frac{\sin x}{x}}{1+\frac{\tan x}{x}}

    $
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  2. #2
    Senior Member
    Joined
    Nov 2008
    Posts
    461
    Hi.

    Quote Originally Posted by thangbe View Post
    Please help me to prove this.


    $\displaystyle \frac{\sin x}{x+\tan x}=\frac{\frac{\sin x}{x}}{1+\frac{\tan x}{x}}

    $
    My idea on this problem is

    $\displaystyle \frac{sin}{x+tan(x)} =\frac{sin}{\frac{(x+tan(x))*x}{x}} = \frac{1}{x} \frac{sin}{\frac{(x+tan(x))}{x}}$

    $\displaystyle = \frac{1}{x}\frac{sin(x)}{[x/x] + tan(x)/x}$

    $\displaystyle = \frac{sin(x)/x}{[1] + tan(x)/x}$

    Do you understand?

    Regards,
    Rapha
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