Need help :)

**thangbe** · February 5th 2009, 05:58 PM

Please help me to prove this.

$\frac{\sin x}{x+\tan x}=\frac{\frac{\sin x}{x}}{1+\frac{\tan x}{x}}<br /> <br />$

**Rapha** · February 5th 2009, 06:15 PM

Hi.

Originally Posted by thangbe

Please help me to prove this.

$\frac{\sin x}{x+\tan x}=\frac{\frac{\sin x}{x}}{1+\frac{\tan x}{x}}<br /> <br />$

My idea on this problem is

$\frac{sin}{x+tan(x)} =\frac{sin}{\frac{(x+tan(x))*x}{x}} = \frac{1}{x} \frac{sin}{\frac{(x+tan(x))}{x}}$

$= \frac{1}{x}\frac{sin(x)}{[x/x] + tan(x)/x}$

$= \frac{sin(x)/x}{[1] + tan(x)/x}$

Do you understand?

Regards,
Rapha

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