1. ## [SOLVED] Pre-Cal/Trig Proofs

I don't even know where to start.
Also, I need help on this problem: tan(x) + sec(x) = cos(x)/(1-sinx)
I've started on the second one, but got stuck. I would greatly appreciate any help.

2. for the first problem, if you simply turn your sin^2(x) into 1-cos^2(x) and combine like terms they should be equal right off the bat. It took me forever to come up with that though, and i can't think of what to do for the second one but just try converting everything into sin's and cos's to start. I find it helps when i can't think of what to do. Hope i could help

3. Thanks! Now that I know how to do it, it seems simple

I did turn everything in the second problem to sin's and cos's, but came up with almost the opposite answer that I'm supposed to have. (sinx+1)/cosx.

4. Originally Posted by Purpledog100
Thanks! Now that I know how to do it, it seems simple

I did turn everything in the second problem to sin's and cos's, but came up with almost the opposite answer that I'm supposed to have. (sinx+1)/cosx.
now rationalize by multiplying Numerator and Denominator by (1 - sin x)

$\displaystyle \frac {1+\sin x}{\cos x}$

$\displaystyle =\frac {1+\sin x}{\cos x}\times \frac {1-\sin x}{1-\sin x}$

$\displaystyle =\frac {1-\sin^2 x}{\cos x(1-\sin x)}$

Now change $\displaystyle 1-\sin^2 x$ into $\displaystyle \cos^2 x$ in the numerator

can you finish ???

5. Yep, I got it. Thanks a lot!