# Math Help - Trigonometry

1. ## Trigonometry

If Secθ=5 tanθ=2√6

How would I go about finding cot(90°
-θ)?

2. Originally Posted by PhillyViDat
If Secθ=5 tanθ=2√6

How would I go about finding cot(90°
-θ)?
Hint: $\cot x = \frac 1{\tan x}$ and $\tan (A - B) = \frac {\tan A - \tan B}{1 + \tan A \tan B}$

3. A known complement identity is that $\tan{\theta} = \cot{\left(\frac{\pi}{2}-\theta\right)}$