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Math Help - Trigonometry

  1. #1
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    Smile Trigonometry

    If Secθ=5 tanθ=2√6

    How would I go about finding cot(90
    -θ)?
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by PhillyViDat View Post
    If Secθ=5 tanθ=2√6

    How would I go about finding cot(90
    -θ)?
    Hint: \cot x = \frac 1{\tan x} and \tan (A - B) = \frac {\tan A - \tan B}{1 + \tan A \tan B}
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  3. #3
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    A known complement identity is that \tan{\theta} = \cot{\left(\frac{\pi}{2}-\theta\right)}
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