I need help on solving the area of a triangle with the formula
Area = 1/2 ab sin C
If anyone knows how to do this please post thankyou
Yes, the another formula for area of a triangle is $\displaystyle = \frac{1}{2} ab \sin C$.
where a and b are two sides and C is included angle. Please mention the exact problem. Do you need to prove this formula or what???
The formula for arrea of a triangle is
Area of triangle ABC $\displaystyle = \frac{1}{2}ab \;\sin C$
Area of triangle ABC $\displaystyle = \frac{1}{2}bc \;\sin A$
Area of triangle ABC $\displaystyle = \frac{1}{2}ca \;\sin B$
Please DO NOT DOUBLE-POST the same question again. It wastes everybody's time.