Thread: Several Problems Trig

1. y=cot(x-(pi/6))


What is the first negative asymptote?

Originally Posted by qbkr21

1. y=cot(x-(pi/6))


What is the first negative asymptote?

?

RonL

No thats not the correct answer I have already tried it...

Originally Posted by qbkr21

No thats not the correct answer I have already tried it...

Opps negative - missed that

Originally Posted by qbkr21

1. y=cot(x-(pi/6))


What is the first negative asymptote?

hello,

the cot-function is not defined for

Then calculate x if


I've got the the first negative asymptote at

EB

Ok yea that right, great thanks


But what formula did you use. Keep in mind that I am in Pre-Calc

Originally Posted by qbkr21

Ok yea that right, great thanks


But what formula did you use. Keep in mind that I am in Pre-Calc

The vertical asymtotes occur where tan(x-pi/6) is zero (and so the cot goes
to infinity), which are the points where x-pi/6=n pi, n=0, +/-1, +/-2, ....

RonL

(and checking by ploting the graph of tan(x-pi/6) and or cot(x-pi/6))