1. ## Several Problems Trig

1. y=cot(x-(pi/6))

What is the first negative asymptote?

2. Originally Posted by qbkr21
1. y=cot(x-(pi/6))

What is the first negative asymptote?
$x=\pi/6$?

RonL

3. ## Re:

4. Originally Posted by qbkr21
Opps negative - missed that

$-5\pi/6$

5. Originally Posted by qbkr21
1. y=cot(x-(pi/6))

What is the first negative asymptote?
hello,

the cot-function is not defined for $x \in \{ ...-2\pi, -\pi, 0, \pi, 2\pi...\}$

Then calculate x if
$x-\frac{\pi}{6} = k \cdot \pi, \ k \in \mathbb{Z}$

I've got the the first negative asymptote at $x=-\frac{5}{6} \pi$

EB

6. ## Re:

Ok yea that right, great thanks

But what formula did you use. Keep in mind that I am in Pre-Calc

7. Originally Posted by qbkr21
Ok yea that right, great thanks

But what formula did you use. Keep in mind that I am in Pre-Calc
The vertical asymtotes occur where tan(x-pi/6) is zero (and so the cot goes
to infinity), which are the points where x-pi/6=n pi, n=0, +/-1, +/-2, ....

RonL

(and checking by ploting the graph of tan(x-pi/6) and or cot(x-pi/6))