Hello, Greenb!
Is this the problem?
On the argand diagram, we have:. .FindHence: .Code:* : * 169 120 : * : * θ - - + - - - * - - - - -119
We have: .
And we want: . .[1]
Using half-angle identities:
. .
. .
Substitute into [1]: .
Ah I forgot that |z| equals the hypotenuse, but I'm not with you all the way on the half angle identities part, seeing that its a cubicequation, it should have two roots.
And what if the equation was;
could it be solved the same way?
I'm Swedish by the way so sorry if I don't get the termonoligy right.