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Math Help - Trig Identities

  1. #1
    Junior Member casey_k's Avatar
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    Trig Identities

    _
    Attached Thumbnails Attached Thumbnails Trig Identities-untitled3.jpg  
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by casey_k View Post
    _
    apply these identities to the left hand side:

    \cot x = \frac {\cos x}{\sin x}
    1 - \sin^2 x = \cos^2 x


    then apply these to the right:

    \tan x = \frac {\sin x}{\cos x}
    1 - \cos^2 x = \sin^2 x
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  3. #3
    MHF Contributor
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    Quote Originally Posted by casey_k View Post
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    \frac{ \cot x}{1 - \sin ^2 x} { ? = } \frac{ \tan x}{1 - \cos ^2 x}

    \frac{ \cot x}{ \cos ^2 x} { ? = } \frac{ \tan x}{\sin ^2 x}

    \frac{1}{\tan x} \frac{ 1}{ \cos ^2 x} { ? = } \frac{ \tan x}{\sin ^2 x}

    where  ? = is a question - is this true. Do you see it from here?
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