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Math Help - Sine

  1. #1
    ADY
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    Sine

    If you have

     Y = sin (x) - 0. 6

    How could i show the sine curve on my calculator for

    X = 0 to 360 \circ

    Thanks
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  2. #2
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    Quote Originally Posted by ADY View Post
    If you have

     Y = sin (x) - 0. 6

    How could i show the sine curve on my calculator for

    X = 0 to 360 \circ

    Thanks
    This is just a regular sine function that has been shifted down the y axis by 0.6 units.

    So it peaks at 0.4, troughs at -1.6, and it's mid point is -0.6.
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  3. #3
    ADY
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    is that with X set to 0 to 360
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    Quote Originally Posted by ADY View Post
    is that with X set to 0 to 360
    Throughout the entire interval.
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  5. #5
    ADY
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    so how can i find the two solutions to the equation? in the peaks?
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  6. #6
    ADY
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     <br />
x= - 4.712<br />

    x= 1.5707

    ?
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  7. #7
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    Quote Originally Posted by ADY View Post
    so how can i find the two solutions to the equation? in the peaks?
    What do you mean by SOLVE it?

    You have one equation and two unknowns  x \text{ and } y . It is not solveable. What is it you are trying to find? I thought you only wanted to graph it.
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  8. #8
    ADY
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    well now ive graphed it - how can i find the 2 solutions of that equation that are between 0 - 360 degrees?
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  9. #9
    Senior Member mollymcf2009's Avatar
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    What are you trying to solve for? Is this the way the question was worded? Can you give me the question exactly as it appears in your book? I don't know how to help you because I can't figure out what it is you solving for
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  10. #10
    ADY
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    2 solutions between

    sin(x) - 0.6 = 0

    between 0 and 360degree

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  11. #11
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    Quote Originally Posted by ADY View Post
    2 solutions between

    sin(x) - 0.6 = 0

    between 0 and 360degree

    That looks much better.

    Graphically the solutions should be where the curve crosses the x-axis (That's where your output equals to zero).
    Algebraically, you will need to solve for x by using the sin^{-1} key on your calculator somewhere.
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  12. #12
    Senior Member mollymcf2009's Avatar
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    Ok, now I see what you need to do. The sin(x) curve has an infinite domain , but comes back to the x axis (where y equals zero)at x = 0 and at x= pi. In the case of this problem, the sine curve is shifted down .06. So it won't = 0 at x=0 or pi, it will be 0 somewhere just larger than 0 and pi. ( I'm guessing probably at .06). As far as from 0 to 2pi ( or in your case 360 deg) you will actually have 3 answers. The solutions are the x values on the curve when y = 0
    Does that make sense? Good luck!
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  13. #13
    ADY
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    Quote Originally Posted by chabmgph View Post
    That looks much better.

    Graphically the solutions should be where the curve crosses the x-axis (That's where your output equals to zero).
    Algebraically, you will need to solve for x by using the sin^{-1} key on your calculator somewhere.
    Could you explain how to do that please chap
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  14. #14
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    Quote Originally Posted by chabmgph View Post
    That looks much better.

    Graphically the solutions should be where the curve crosses the x-axis (That's where your output equals to zero).
    Algebraically, you will need to solve for x by using the sin^{-1} key on your calculator somewhere.
    Quote Originally Posted by ADY View Post
    Could you explain how to do that please chap
    You can do this graphically if you own a graphing calculator. However, depending on what model you have, the procedure would be different. And I believe there is a section in this forum devoted to calculator use.

    To do this algebraically,
    \sin (x) - 0.6 =0
    \sin (x) =0.6
    x=\sin^{-1}(0.6)
    Then to find a approximation of x, find the sin^{-1} key on your calculator and calculate what sin^{-1}(0.6) is.
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  15. #15
    ADY
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    How can there be two answers then? because of where the curve crosses the x axis?
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