If you have
$\displaystyle Y = sin (x) - 0. 6$
How could i show the sine curve on my calculator for
X = 0 to 360$\displaystyle \circ$
Thanks
Ok, now I see what you need to do. The sin(x) curve has an infinite domain , but comes back to the x axis (where y equals zero)at x = 0 and at x= pi. In the case of this problem, the sine curve is shifted down .06. So it won't = 0 at x=0 or pi, it will be 0 somewhere just larger than 0 and pi. ( I'm guessing probably at .06). As far as from 0 to 2pi ( or in your case 360 deg) you will actually have 3 answers. The solutions are the x values on the curve when y = 0
Does that make sense? Good luck!
You can do this graphically if you own a graphing calculator. However, depending on what model you have, the procedure would be different. And I believe there is a section in this forum devoted to calculator use.
To do this algebraically,
$\displaystyle \sin (x) - 0.6 =0$
$\displaystyle \sin (x) =0.6$
$\displaystyle x=\sin^{-1}(0.6)$
Then to find a approximation of x, find the $\displaystyle sin^{-1}$ key on your calculator and calculate what $\displaystyle sin^{-1}(0.6)$ is.