If you have

How could i show the sine curve on my calculator for

X = 0 to 360

Thanks

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- January 21st 2009, 06:56 AMADYSine
If you have

How could i show the sine curve on my calculator for

X = 0 to 360

Thanks - January 21st 2009, 06:59 AMMush
- January 21st 2009, 07:10 AMADY
is that with X set to 0 to 360

- January 21st 2009, 07:25 AMMush
- January 21st 2009, 07:36 AMADY
so how can i find the two solutions to the equation? in the peaks?

- January 21st 2009, 07:40 AMADY

? - January 21st 2009, 08:05 AMMush
- January 21st 2009, 08:48 AMADY
well now ive graphed it - how can i find the 2 solutions of that equation that are between 0 - 360 degrees?

- January 21st 2009, 09:24 AMmollymcf2009
What are you trying to solve for? Is this the way the question was worded? Can you give me the question exactly as it appears in your book? I don't know how to help you because I can't figure out what it is you solving for

- January 21st 2009, 09:54 AMADY
2 solutions between

between 0 and 360degree

(Rock) - January 21st 2009, 10:55 AMchabmgph
- January 21st 2009, 12:08 PMmollymcf2009
Ok, now I see what you need to do. The sin(x) curve has an infinite domain , but comes back to the x axis (where y equals zero)at x = 0 and at x= pi. In the case of this problem, the sine curve is shifted down .06. So it won't = 0 at x=0 or pi, it will be 0 somewhere just larger than 0 and pi. ( I'm guessing probably at .06). As far as from 0 to 2pi ( or in your case 360 deg) you will actually have 3 answers. The solutions are the x values on the curve when y = 0

Does that make sense? Good luck! - January 22nd 2009, 09:58 AMADY
- January 22nd 2009, 12:31 PMchabmgph
You can do this graphically if you own a graphing calculator. However, depending on what model you have, the procedure would be different. And I believe there is a section in this forum devoted to calculator use.

To do this algebraically,

Then to find a approximation of x, find the key on your calculator and calculate what is. - January 23rd 2009, 02:08 AMADY
How can there be two answers then? because of where the curve crosses the x axis?