If you have

$\displaystyle Y = sin (x) - 0. 6$

How could i show the sine curve on my calculator for

X = 0 to 360$\displaystyle \circ$

Thanks

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- Jan 21st 2009, 05:56 AMADYSine
If you have

$\displaystyle Y = sin (x) - 0. 6$

How could i show the sine curve on my calculator for

X = 0 to 360$\displaystyle \circ$

Thanks - Jan 21st 2009, 05:59 AMMush
- Jan 21st 2009, 06:10 AMADY
is that with X set to 0 to 360

- Jan 21st 2009, 06:25 AMMush
- Jan 21st 2009, 06:36 AMADY
so how can i find the two solutions to the equation? in the peaks?

- Jan 21st 2009, 06:40 AMADY
$\displaystyle

x= - 4.712

$

$\displaystyle x= 1.5707$

? - Jan 21st 2009, 07:05 AMMush
- Jan 21st 2009, 07:48 AMADY
well now ive graphed it - how can i find the 2 solutions of that equation that are between 0 - 360 degrees?

- Jan 21st 2009, 08:24 AMmollymcf2009
What are you trying to solve for? Is this the way the question was worded? Can you give me the question exactly as it appears in your book? I don't know how to help you because I can't figure out what it is you solving for

- Jan 21st 2009, 08:54 AMADY
2 solutions between

$\displaystyle sin(x) - 0.6 = 0$

between 0 and 360degree

(Rock) - Jan 21st 2009, 09:55 AMchabmgph
- Jan 21st 2009, 11:08 AMmollymcf2009
Ok, now I see what you need to do. The sin(x) curve has an infinite domain , but comes back to the x axis (where y equals zero)at x = 0 and at x= pi. In the case of this problem, the sine curve is shifted down .06. So it won't = 0 at x=0 or pi, it will be 0 somewhere just larger than 0 and pi. ( I'm guessing probably at .06). As far as from 0 to 2pi ( or in your case 360 deg) you will actually have 3 answers. The solutions are the x values on the curve when y = 0

Does that make sense? Good luck! - Jan 22nd 2009, 08:58 AMADY
- Jan 22nd 2009, 11:31 AMchabmgph
You can do this graphically if you own a graphing calculator. However, depending on what model you have, the procedure would be different. And I believe there is a section in this forum devoted to calculator use.

To do this algebraically,

$\displaystyle \sin (x) - 0.6 =0$

$\displaystyle \sin (x) =0.6$

$\displaystyle x=\sin^{-1}(0.6)$

Then to find a approximation of x, find the $\displaystyle sin^{-1}$ key on your calculator and calculate what $\displaystyle sin^{-1}(0.6)$ is. - Jan 23rd 2009, 01:08 AMADY
How can there be two answers then? because of where the curve crosses the x axis?