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Math Help - 2 trig Questions

  1. #1
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    2 trig Questions

    #1
    A tunne must be constructed through a mountain. The angle of elevation from one side of the mountain is 38.2 . The angle of elevation fromthe other side of the mountain is 27.4 . The height of the mountain is 575m. What is the lenght of the tunnel through this mountain ?

    Is the other end of the mountain the upper corner of a right triangle, or the lower ? ANd does anyone have the formula or a similar question I could copy the steps from ?

    #2
    A vertical light pole on a hillside casts a shadow of 55m long down the hill. If the angle of elevation of the sun is 48.3 and the angle of incilination of the hill is 21.4 . Find the height of the pole.

    I know what the angle of elevasion and depression is, but what is the angle of incillination ? I dont get this question.

    Fast answeres would be nice, its almost 3 am and i can barely force my yeyes to be open: Due date of this Assignment is tomorrow, its an online submission which has to happen before 11 am
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  2. #2
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    Q1) I think the answer should be = 575*Cot(38.2) + 575*cot(27.4)
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  3. #3
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    #1
    A tunne must be constructed through a mountain. The angle of elevation from one side of the mountain is 38.2 . The angle of elevation fromthe other side of the mountain is 27.4 . The height of the mountain is 575m. What is the lenght of the tunnel through this mountain ?


    the figure is attached
    Attached Thumbnails Attached Thumbnails 2 trig Questions-untitled.jpg  
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  4. #4
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    #2
    A vertical light pole on a hillside casts a shadow of 55m long down the hill. If the angle of elevation of the sun is 48.3 and the angle of incilination of the hill is 21.4 . Find the height of the pole.



    see the bigure below
    Attached Thumbnails Attached Thumbnails 2 trig Questions-untitled2.jpg  
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  5. #5
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    Quote Originally Posted by sumit2009 View Post
    Q1) I think the answer should be = 575*Cot(38.2) + 575*cot(27.4)

    Cant find cot in any online calculator :S
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  6. #6
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    Found out that cot = 1/tan(x)

    using this my output is:

    ((1 / tan(575)) * 38.2) + ((1 / tan(575)) * 27.4) = 738.934121

    So the lenght of the tunnel is 738.9 m.

    Does "*" represent the degree sign ?



    Right or wrong ?
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  7. #7
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    Quote Originally Posted by Serialkisser
    Found out that cot = 1/tan(x)

    using this my output is:

    ((1 / tan(575)) * 38.2) + ((1 / tan(575)) * 27.4) = 738.934121

    So the lenght of the tunnel is 738.9 m.

    Does "*" represent the degree sign ?



    Right or wrong ?
    question-1

    [/I][/COLOR]575*Cot(38.2) + 575*cot(27.4) { here * represents multiplication not degree sign}

    i.e. 575 X Cot(38.2degree) + 575 X cot(27.4degree)

    or, 575 / tan(38.2degree) + 575 / tan(27.4degree)
    Last edited by mr fantastic; January 19th 2009 at 08:08 AM.
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  8. #8
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    tan(38.2degree) = 0.7869
    tan(27.4degree) = 0.5183

    575 / 0.7869 +575/0.5183
    =(1109.39+730.69)
    =1840.08 m approx
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  9. #9
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    Quote Originally Posted by sumit2009 View Post
    question-1

    [/i][/color]575*Cot(38.2) + 575*cot(27.4) { here * represents multiplication not degree sign}

    i.e. 575 X Cot(38.2degree) + 575 X cot(27.4degree)

    or, 575 / tan(38.2degree) + 575 / tan(27.4degree)

    (575 / tan(38.2 degree)) + (575 / tan(27.4 degree)) = 1 839.98211


    So the Tunnel is 1 839.98211 m

    Correct ?
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  10. #10
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    Quote Originally Posted by Serialkisser View Post
    (575 / tan(38.2 degree)) + (575 / tan(27.4 degree)) = 1 839.98211


    So the Tunnel is 1 839.98211 m

    Correct ?

    YES........
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