Solve the equation for a in [0, 2pie]

A.) cosē(a) + 3cos(a) = -cos(a)

B.)sin(2a) = cos(a)

Printable View

- Jan 13th 2009, 08:51 PMVkLTrig question: with intervals
Solve the equation for a in [0, 2pie]

A.) cosē(a) + 3cos(a) = -cos(a)

B.)sin(2a) = cos(a) - Jan 13th 2009, 09:08 PMThePerfectHacker
Add to both sides to get and now . Therefore, or . The second condition, is impossible because . The first condition is . That happens when

Quote:

B.)sin(2a) = cos(a)