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Math Help - Trigonometry!!

  1. #1
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    Jan 2009
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    Trigonometry!!

    I have had some question on trig and i could easily find the lines like e.g. whats the size of A-B
    However when im doing this i either have to do SIN the angle ,TAN thhe angle,COS the angle.
    But what happens if there is no angle.
    This is what i do..
    Firstly lets say
    the angle is called "alpha" and we are using tangent aand opposite,
    so we use TAN
    next i did is
    TAN "alpha" = lets say the sides are 6 which is the opposite and 3 the tangent
    all i did was TAN "alpha" = 6/3
    Now i did this on my calculator.
    INVERSE TAN 3
    iam shure i did everythign correct apart from last part so can someone explain please.
    Thank you.
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  2. #2
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    Trigonometry

    Hello Zakir
    Quote Originally Posted by Zakir View Post
    I have had some question on trig and i could easily find the lines like e.g. whats the size of A-B
    However when im doing this i either have to do SIN the angle ,TAN thhe angle,COS the angle.
    But what happens if there is no angle.
    This is what i do..
    Firstly lets say
    the angle is called "alpha" and we are using tangent aand opposite,
    so we use TAN
    next i did is
    TAN "alpha" = lets say the sides are 6 which is the opposite and 3 the tangent
    all i did was TAN "alpha" = 6/3
    Now i did this on my calculator.
    INVERSE TAN 3
    iam shure i did everythign correct apart from last part so can someone explain please.
    Thank you.
    If \tan \alpha = 6/3, then you will need INVERSE TAN 2, because 6/3 = 2.

    This gives \alpha = 63.4^o<br />

    Is that what you needed to know?

    Grandad
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  3. #3
    A riddle wrapped in an enigma
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    Jan 2008
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    Big Stone Gap, Virginia
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    Quote Originally Posted by Zakir View Post
    I have had some question on trig and i could easily find the lines like e.g. whats the size of A-B
    However when im doing this i either have to do SIN the angle ,TAN thhe angle,COS the angle.
    But what happens if there is no angle.
    This is what i do..
    Firstly lets say
    the angle is called "alpha" and we are using tangent aand opposite,
    so we use TAN
    next i did is
    TAN "alpha" = lets say the sides are 6 which is the opposite and 3 the tangent
    all i did was TAN "alpha" = 6/3
    Now i did this on my calculator.
    INVERSE TAN 3
    iam shure i did everythign correct apart from last part so can someone explain please.
    Thank you.
    Hello Zakir,

    I'm having a little trouble following what you're asking, but suffice it to say that the tangent function is the ratio of the oppsite side to the adjacent side of a right triangle.

    \tan \alpha = \frac{6}{3}

    \arctan 2=\alpha
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