Prove that

tan A - (sec A sin^3A / 1 + cos A ) = sin A

(From here on I don't know what to do aside from subtracting it)(sin A / cos A) - (sin^3A / cos A + cos^2 A )

Obtained from my Workings

Prove that

sin^3 A / cos A - cos^3A = tan A

Obtained from my Workings: Can't think of Any

Thanks, hoping for a fast reply

Arnold,