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Math Help - trigonometry problem

  1. #1
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    trigonometry problem

    cos α= -0,007275 α=? (α is in grad ) how is this problem solved ?
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  2. #2
    Super Member craig's Avatar
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    you take the arccos/inverse cos of both sides of the equation.

    On your calculator the inverse cos button will look some thing like this \cos^-1
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  3. #3
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    Let's start by reviewing what the trig functions mean. The sin(a) = b tells you that the ratio b is made up of taking some angle a and taking its opposite side divided by the hypotenuse of the resultant right triangle. This let's us find a ratio b given some angle a. However, we're going to need to use a slightly different method to find a given some ratio b.

    The inverse trig functions, as mentioned above, are sort of like the opposite operation to regular trig functions. sin^-1, cos^-1, and tan^-1 are all inverse functions (they are also sometimes written as arcsin, arccos, and arctan - don't worry, they mean exactly the same thing). The inverse trig functions tell us that, given some ratio b, what the angle would have to be. So, if sin(a) = b, then arcsin(b) = a.

    The answer posted above is correct, and I hope this clarifies how to solve the problem.
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  4. #4
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    problem

    Quote Originally Posted by blaugrana_paok4 View Post
    cos α= -0,007275 α=? (α is in grad ) how is this problem solved ?
    slove 1-2sin2A=cos3a+sin3a/cos A-sin A
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