Results 1 to 8 of 8

Math Help - In terms of tangent beta

  1. #1
    Junior Member
    Joined
    Aug 2008
    Posts
    35

    In terms of tangent beta

    Express
    (sin BETA + cos BETA)

    ____________________
    in terms of tan Beta how to do???
    (cos BETA)
    Follow Math Help Forum on Facebook and Google+

  2. #2
    A riddle wrapped in an enigma
    masters's Avatar
    Joined
    Jan 2008
    From
    Big Stone Gap, Virginia
    Posts
    2,551
    Thanks
    12
    Awards
    1
    Quote Originally Posted by j0nath0n3 View Post
    Express
    (sin BETA + cos BETA)

    ____________________
    in terms of tan Beta how to do???
    (cos BETA)

    \frac{\sin \beta + \cos \beta}{\cos \beta}=\frac{\sin \beta}{\cos \beta}+\frac{\cos \beta}{\cos \beta}=\tan \beta + 1
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Junior Member
    Joined
    Aug 2008
    Posts
    35
    Quote Originally Posted by masters View Post
    \frac{\sin \beta + \cos \beta}{\cos \beta}=\frac{\sin \beta}{\cos \beta}+\frac{\cos \beta}{\cos \beta}=\tan \beta + 1
    Thanked!
    How about:
    sec theta - sin theta tan theta in terms of cos theta
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Super Member
    Joined
    Jun 2008
    Posts
    792
    Quote Originally Posted by j0nath0n3 View Post
    How about:
    sec theta - sin theta tan theta in terms of cos theta
    \sec{\theta} - \sin{\theta}\tan{\theta} = \frac{1}{\cos{\theta}}- \frac{\sin^2{\theta}}{\cos{\theta}}

    Recall that 1 - \sin^2{\theta} = \cos^2{\theta}. Carry on.
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Junior Member
    Joined
    Aug 2008
    Posts
    35

    Thumbs up

    Quote Originally Posted by Chop Suey View Post
    \sec{\theta} - \sin{\theta}\tan{\theta} = \frac{1}{\cos{\theta}}- \frac{\sin^2{\theta}}{\cos{\theta}}

    Recall that 1 - \sin^2{\theta} = \cos^2{\theta}. Carry on.
    What Identity is this?

    Is \sin^2{\theta} equal to \sin^2 {\theta}+ \cos^2{\theta} = 1?
    Sorry I am very confused!
    Follow Math Help Forum on Facebook and Google+

  6. #6
    Super Member
    Joined
    Jun 2008
    Posts
    792
    Quote Originally Posted by j0nath0n3 View Post
    What Identity is this?
    \sin^2{x}+\cos^2{x}=1 \iff \sin^2{x} = 1-\cos^2{x} \iff \cos^2{x} = 1-\sin^2{x}

    This is known as the Pythagorean identity.
    Follow Math Help Forum on Facebook and Google+

  7. #7
    Junior Member
    Joined
    Aug 2008
    Posts
    35
    Quote Originally Posted by Chop Suey View Post
    \sin^2{x}+\cos^2{x}=1 \iff \sin^2{x} = 1-\cos^2{x} \iff \cos^2{x} = 1-\sin^2{x}

    This is known as the Pythagorean identity.
    So in terms of cos thetha sec thetha - sin theta tan theta in terms of cos theta equals
    1

    _____________

    cos squared theta
    ?
    Follow Math Help Forum on Facebook and Google+

  8. #8
    A riddle wrapped in an enigma
    masters's Avatar
    Joined
    Jan 2008
    From
    Big Stone Gap, Virginia
    Posts
    2,551
    Thanks
    12
    Awards
    1
    Quote Originally Posted by Chop Suey View Post
    \sec{\theta} - \sin{\theta}\tan{\theta} = \frac{1}{\cos{\theta}}- \frac{\sin^2{\theta}}{\cos{\theta}}

    Recall that 1 - \sin^2{\theta} = \cos^2{\theta}. Carry on.
    Look Jonathon,

    Chop Suey has taken it to the very last step. There's not much else to do here.

    \sec{\theta} - \sin{\theta}\tan{\theta} = \frac{1}{\cos{\theta}}- \frac{\sin^2{\theta}}{\cos{\theta}}=\frac{1-\sin^2 \theta}{\cos \theta}=\frac{\cos^2 \theta}{\cos \theta}=?
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 4
    Last Post: December 15th 2010, 04:10 PM
  2. Beta pdf
    Posted in the Advanced Statistics Forum
    Replies: 1
    Last Post: October 27th 2009, 07:35 PM
  3. beta distribution
    Posted in the Advanced Statistics Forum
    Replies: 1
    Last Post: May 13th 2009, 07:39 PM
  4. |alpha-beta|
    Posted in the Algebra Forum
    Replies: 1
    Last Post: January 30th 2009, 07:28 AM
  5. derive cos(alpha+beta) sin(alpha+beta)?
    Posted in the Trigonometry Forum
    Replies: 3
    Last Post: December 7th 2008, 04:27 PM

Search Tags


/mathhelpforum @mathhelpforum