Express
(sin BETA + cos BETA)in terms of tan Beta how to do???
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(cos BETA)
Look Jonathon,
Chop Suey has taken it to the very last step. There's not much else to do here.
$\displaystyle \sec{\theta} - \sin{\theta}\tan{\theta} = \frac{1}{\cos{\theta}}- \frac{\sin^2{\theta}}{\cos{\theta}}=\frac{1-\sin^2 \theta}{\cos \theta}=\frac{\cos^2 \theta}{\cos \theta}=?$