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Math Help - Trig. Finding the general solution

  1. #1
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    Trig. Finding the general solution

    2 cos x = sec x


    Thank you ahead of time.
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  2. #2
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    Quote Originally Posted by akpolish View Post
    2 cos x = sec x


    Thank you ahead of time.
    Hint:  \sec x = \frac{1}{\cos x}

    Try to solve for \cos x and see.
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  3. #3
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    Thank you for the hint but I still don't understand.
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  4. #4
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    Quote Originally Posted by akpolish View Post
    2 cos x = sec x


    Thank you ahead of time.
    Quote Originally Posted by akpolish View Post
    Thank you for the hint but I still don't understand.

    2 \cos x = \sec x
    2 \cos x =\frac{1}{\cos x} \text{ \; \; \; \;  (}\cos x \neq 0)
    2 \cos^2 x =1
     \cos^2 x =\frac{1}{2}
     \cos x =\pm\frac{\sqrt{2}}{2}

    Now see if you can find the angles which gives you these value.
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