Trig. Finding the general solution

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December 16th 2008, 04:14 PM
akpolish

Trig. Finding the general solution

2 cos x = sec x

Thank you ahead of time.
December 16th 2008, 04:23 PM
chabmgph

Quote:

Originally Posted by akpolish

2 cos x = sec x

Thank you ahead of time.

Hint: $\sec x = \frac{1}{\cos x}$

Try to solve for $\cos x$ and see.
December 16th 2008, 04:25 PM
akpolish

Thank you for the hint but I still don't understand.
December 17th 2008, 03:36 PM
chabmgph

Quote:

Originally Posted by akpolish

2 cos x = sec x

Thank you ahead of time.

Quote:

Originally Posted by akpolish

Thank you for the hint but I still don't understand.

$2 \cos x = \sec x$
$2 \cos x =\frac{1}{\cos x} \text{ \; \; \; \; (}\cos x \neq 0$ )
$2 \cos^2 x =1$
$\cos^2 x =\frac{1}{2}$
$\cos x =\pm\frac{\sqrt{2}}{2}$

Now see if you can find the angles which gives you these value.

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