Find modulus and argument of:
The correct answer is:
Could someone explain to me why I have to subtract from my final answer.
Thanks
Hello,
I don't like using the arctan function. It makes problems because of the restrictions of the domain ><
Note that the cosine and the sine are both negative. So will be in the third quadrant. That is lies between
With the specific trig values you should know,
You also could've written :
Hello, r_maths!
Find modulus and argument of:
. . . . no, you mean:
The correct answer is: . . . . . or
Could someone explain to me why I have to subtract from my final answer.
Plot the complex number on the Argand diagram.Code:| | -2 | - - + - - + - - - - | /| __ | / | -√12 | / | | / | |/ | * | |
The argument is an angle in Quadrant 3.