# Thread: How do I use reference angles to find these answers?

1. ## How do I use reference angles to find these answers?

The problem says use reference angle method and gives me this:

1.) tanx = sq root of 3, 0< x < 4pie

2.) 2sin^2(x) + cosx = 1, 0< x< 2pie

I mean, I understand enough of sine and cosine to understand what it's asking, but I don't know exactly the proper steps to find the answer. Any help would be greatly appreciated.

2. Originally Posted by I_needhelp
The problem says use reference angle method and gives me this:

1.) tanx = sq root of 3, 0< x < 4pie

2.) 2sin^2(x) + cosx = 1, 0< x< 2pie

I mean, I understand enough of sine and cosine to understand what it's asking, but I don't know exactly the proper steps to find the answer. Any help would be greatly appreciated.
1. $\tan{x} = \sqrt{3}, 0 < x < 4\pi$

$x = \tan^{-1}{\sqrt{3}}$

There will be an answer in the first quadrant, and an answer in the third.

So $x = \{\frac{\pi}{3},\pi + \frac{\pi}{3}\}$.

Also, every iteration of the unit circle will have 2 solutions. This can be represented by adding $2n\pi$, where $n$ is an integer.

So $x = \{\frac{\pi}{3}, \frac{4\pi}{3}\} + 2n\pi$.

Letting n equal different values enables you to find all solutions in the domain.

Let $n = 0$ you have $x = \{\frac{\pi}{3}, \frac{4\pi}{3}\}$

Let $n = 1$, you have $x = \{\frac{7\pi}{3}, \frac{10\pi}{3}\}$.

Any $n > 1$ has solutions out of the domain.

So all the solutions are

$x=\{\frac{\pi}{3}, \frac{4\pi}{3}, \frac{7\pi}{3}, \frac{10\pi}{3}\}$.