1.

There will be an answer in the first quadrant, and an answer in the third.

So .

Also, every iteration of the unit circle will have 2 solutions. This can be represented by adding , where is an integer.

So .

Letting n equal different values enables you to find all solutions in the domain.

Let you have

Let , you have .

Any has solutions out of the domain.

So all the solutions are

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