trigonometry recatangular to polar form

**robasc** · Dec 11th 2008, 12:01 AM

I am trying to convert this rectangular equation to polar form.

$ (x-2)^2 + y^2 = 4 $

$ (r cos \theta - 2)^2 + r (sin \theta)^2 = 4 $

I get lost after this,

could someone please help?

**mr fantastic** · Dec 11th 2008, 02:06 AM

Originally Posted by robasc

I am trying to convert this rectangular equation to polar form.

$ (x-2)^2 + y^2 = 4 $

$ (r cos \theta - 2)^2 + ( {\color{red}r} sin \theta)^2 = 4 $

I get lost after this,

could someone please help?

Note the typo I've fixed (in red). Now expand $(r \cos \theta - 2)^2$ and simplify the resulting expression (the Pythagorean Identity is your friend).

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