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Math Help - trigonometry recatangular to polar form

  1. #1
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    trigonometry recatangular to polar form

    I am trying to convert this rectangular equation to polar form.

    <br />
(x-2)^2 + y^2 = 4<br />

    <br />
(r cos \theta - 2)^2 + r (sin \theta)^2 = 4<br />

    I get lost after this,

    could someone please help?
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  2. #2
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    Quote Originally Posted by robasc View Post
    I am trying to convert this rectangular equation to polar form.

    <br />
(x-2)^2 + y^2 = 4<br />

    <br />
(r cos \theta - 2)^2 + ( {\color{red}r} sin \theta)^2 = 4<br />

    I get lost after this,

    could someone please help?
    Note the typo I've fixed (in red). Now expand (r \cos \theta - 2)^2 and simplify the resulting expression (the Pythagorean Identity is your friend).
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