trigonometry recatangular to polar form

**robasc** · December 11th 2008, 01:01 AM

I am trying to convert this rectangular equation to polar form.

$ (x-2)^2 + y^2 = 4 $

$ (r cos \theta - 2)^2 + r (sin \theta)^2 = 4 $

I get lost after this,

could someone please help?

**mr fantastic** · December 11th 2008, 03:06 AM

Originally Posted by robasc

I am trying to convert this rectangular equation to polar form.

$ (x-2)^2 + y^2 = 4 $

$ (r cos \theta - 2)^2 + ( {\color{red}r} sin \theta)^2 = 4 $

I get lost after this,

could someone please help?

Note the typo I've fixed (in red). Now expand $(r \cos \theta - 2)^2$ and simplify the resulting expression (the Pythagorean Identity is your friend).

Thread: trigonometry recatangular to polar form

LinkBack

Thread Tools

Display

trigonometry recatangular to polar form

Similar Math Help Forum Discussions

Polar form

Rectangular form into Polar Form

Converting from Polar form to Rectangular form

Polar Form

From polar form to rectangular form..help!

Search Tags