2tan x + 2 = 0 solve for x to nearest degree in interval of 0 great or equal x greater or equal to 360 thank you
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Originally Posted by madfreshx 2tan x + 2 = 0 solve for x to nearest degree in interval of 0 great or equal x greater or equal to 360 thank you When is $\displaystyle \tan\left(x\right)=-1$? Hint: there are two angles...one in the second quadrant, and the other is in the fourth quadrant.
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