Verify that √((1-cosx)/(1+cosx)) = (1-cosx)/|sinx|

Printable View

December 10th 2008, 05:47 PM
SMA777

Verify that √((1-cosx)/(1+cosx)) = (1-cosx)/|sinx|

For this problem we're supposed to prove/verify that:

√((1-cosx)/(1+cosx)) = (1-cosx)/|sinx|

Also, if someone could explain why the sinx in the right side has to be absolute value, that would be appreciated. Thank you :)
December 10th 2008, 06:11 PM
skeeter

$\sqrt{\frac{1-\cos{x}}{1+\cos{x}}} \cdot \sqrt{\frac{1-\cos{x}}{1-\cos{x}}} =$

$\frac{1 - \cos{x}}{\sqrt{1 - \cos^2{x}}} =$

$\frac{1 - \cos{x}}{\sqrt{\sin^2{x}}} =$

$\frac{1 - \cos{x}}{|\sin{x}|}$

basic algebra ... $\sqrt{a^2} = |a|$
December 10th 2008, 07:06 PM
SMA777

Thank you, I understand the proof now!

A little clarification in this matter:
|a| = √a^2

is this because its a^2 and not (-a)^2? (So if it were (-a)^2 it'd be -|a| ?)

Thanks!
December 10th 2008, 09:39 PM
Prove It

Quote:

Originally Posted by SMA777

Thank you, I understand the proof now!

A little clarification in this matter:
|a| = √a^2

is this because its a^2 and not (-a)^2? (So if it were (-a)^2 it'd be -|a| ?)

Thanks!

There are always two square roots to any number.

i.e. $\sqrt{a^2} = a$ or $\sqrt{a^2} = -a$

Notice that both answers have a "size" of $a$ .

This "size" is denoted with an absolute value.

So $\sqrt{a^2} = |a|$ is correct, because it's saying the answer is something of "size" $a$ .

All times are GMT -8. The time now is 05:10 PM.

Copyright © 2005-2015 Math Help Forum. All rights reserved.

Copyright © 2005-2014 Math Help Forum. All rights reserved.