I have a test tomrow and i cant do some of the problems on the topic please help. i want to know how to do these before my test tomrow express sin 320degrees as a sin function of a positive acute angle find the value of cos^2 x - 2cos x= 0 thx
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Originally Posted by madfreshx I have a test tomrow and i cant do some of the problems on the topic please help. i want to know how to do these before my test tomrow express sin 320degrees as a sin function of a positive acute angle find the value of cos^2 x - 2cos x= 0 thx 320 degrees is 40 degrees below the (+) x-axis factor out ... at and has no solution.
thank you very much can you also help me with this sinx = - 1/2 solve for x in neareast degree of 0 equal or greater than x equal or greater 360 also for the second question you asnwered for me i made a mistake it is deta not x
Originally Posted by madfreshx thank you very much can you also help me with this sinx = - 1/2 solve for x in neareast degree of 0 equal or greater than x equal or greater 360 also for the second question you asnwered for me i made a mistake it is deta not x theta , not deta ... so, change all the x's to theta's this value is on your unit circle in quad III and IV ... and next time start a new thread for a new question.
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