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Math Help - Quick trig problem...

  1. #1
    Newbie
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    Nov 2008
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    Quick trig problem...

    I'm just doing this question that says:

    Solve for Θ to the nearest hundredth, where 0 ≤ Θ ≤ 2π

    3tanēΘ - 2tanΘ = 1


    The answers are π/4, 2.82, 5π/4, and 5.96

    I don't know how they got 2.82, or 5.96

    I factored (3tanΘ+1)(tanΘ-1)
    tanΘ = 1
    then I used the special triangles, in the first and third quadrant to get π/4, and 5π/4.

    what do I do about
    tanΘ = -1/3?
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  2. #2
    MHF Contributor
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    France
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    Quote Originally Posted by lanvin View Post
    I'm just doing this question that says:

    Solve for Θ to the nearest hundredth, where 0 ≤ Θ ≤ 2π

    3tanēΘ - 2tanΘ = 1


    The answers are π/4, 2.82, 5π/4, and 5.96

    I don't know how they got 2.82, or 5.96

    I factored (3tanΘ+1)(tanΘ-1)
    tanΘ = 1
    then I used the special triangles, in the first and third quadrant to get π/4, and 5π/4.

    what do I do about
    tanΘ = -1/3?
    Hi

    You have to use Arctan function
    Arctan(-1/3) = -0.32 rad
    To find the answers between 0 and 2π, you just have to add π (which gives 2.82 rad) and again π (which gives 5.96 rad) because tan is a π-periodic function
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