i keep on getting the wrong answer but cant work out where im going wrong solve: between 0 and 360 3cos2 = 2cos^2 3(2cos^2 - 1) = 2cos^2 6cos^2 - 3 = 2cos^2 4cos^2 - 3 = 0 cos = sqr 3/4
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Originally Posted by dno i keep on getting the wrong answer but cant work out where im going wrong solve: between 0 and 360 3cos2 = 2cos^2 3(2cos^2 - 1) = 2cos^2 6cos^2 - 3 = 2cos^2 4cos^2 - 3 = 0 cos = sqr 3/4 Where is the unknown? What you've posted is mathemetically meaningless. I assume you mean . In which case your last line should be , that is, and .
Last edited by mr fantastic; December 8th 2008 at 06:00 PM.
Originally Posted by mr fantastic Where is the unknown? What you've posted is mathemetically meaningless. I assume you mean . In which case your last line should be , that is, and . couldnt be bothered to right out the fetas and it makes it more confusing the answers in the back of the book are 30, 150, 210, 330
Last edited by mr fantastic; December 8th 2008 at 06:01 PM. Reason: Fixed the quote of my edit
Originally Posted by dno couldnt be bothered to right out the fetas and it makes it more confusing the answers in the back of the book are 30, 150, 210, 330 I fixed some typos in my previous reply. Go back and look at the final equations you have to solve. They should be simple to solve.
Originally Posted by mr fantastic I fixed some typos in my previous reply. Go back and look at the final equations you have to solve. They should be simple to solve. oh yeah i get it now tanks
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