i keep on getting the wrong answer but cant work out where im going wrong

solve: between 0 and 360

3cos2 = 2cos^2

3(2cos^2 - 1) = 2cos^2

6cos^2 - 3 = 2cos^2

4cos^2 - 3 = 0

cos = sqr 3/4

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- December 8th 2008, 03:04 PMdnoCan someone please tell me where im going wrong
i keep on getting the wrong answer but cant work out where im going wrong

solve: between 0 and 360

3cos2 = 2cos^2

3(2cos^2 - 1) = 2cos^2

6cos^2 - 3 = 2cos^2

4cos^2 - 3 = 0

cos = sqr 3/4 - December 8th 2008, 04:42 PMmr fantastic
- December 8th 2008, 05:56 PMdno
- December 8th 2008, 06:02 PMmr fantastic
- December 8th 2008, 06:22 PMdno