Is there a way to simplify this EQ:
Sin(3t) &(t+2)
& denotes DELTA function
Thanks for help and greets from Mexico
first of all your not making the equation clear but i will try and help you.
if u mean simplifying both equations then it is easy.
=> (sin3t) (t+2) = tsin3t+2sin3t
it is a simple cross muntilplication of both brackets
=> sin3t *t = tsin3t
and
=> sin3t * 2 = 2sin3t
Because of the + sign in (t+2), you add the cross multiplication.
therefore u get:
=> tsin3t+2sin3t
I hope this helps you
Greetings