for 0<a<360 i need to find 'a' from sec^2(a) = 4tan(a)-2 any help would be much appreciated thanks
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Rewrite: $\displaystyle 1-tan^{2}(a)=4tan(a)-2$ Now, bring it all to one side and make a u sub to turn it into a quadratic. Let u=tan(a)
Shouldn't that be $\displaystyle 1+tan^2(a)=4tan(a)-2$? You can remember it by starting with $\displaystyle sin^2(a)+cos^2(a)=1$ and then dividing both sides by $\displaystyle cos^2(a)$ to get $\displaystyle tan^2(a)+1=sec^2(a)$
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