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Thread: bearing

  1. December 7th 2008, 04:00 AM #1
    helloying
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    bearing

    see the attachment
    Attached Thumbnails Attached Thumbnails bearing-img013.jpg  
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  2. December 7th 2008, 06:31 AM #2
    skeeter
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    AF = \frac{h}{\tan(30)}<br />

    BF = \frac{h}{\tan(50)}

    (AF)^2 + (BF)^2 = 96^2

    substitute and solve for h ... then use what you get for h to find either AF or BF, then use the appropriate trig ratio to find the requested bearing.
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