see the attachment
$\displaystyle AF = \frac{h}{\tan(30)}
$
$\displaystyle BF = \frac{h}{\tan(50)}$
$\displaystyle (AF)^2 + (BF)^2 = 96^2$
substitute and solve for h ... then use what you get for h to find either AF or BF, then use the appropriate trig ratio to find the requested bearing.