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Math Help - another trigo question

  1. #1
    Member helloying's Avatar
    Joined
    Jul 2008
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    177

    another trigo question

    see the picture attached.
    Attached Thumbnails Attached Thumbnails another trigo question-img012.jpg  
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  2. #2
    Member Mentia's Avatar
    Joined
    Dec 2008
    From
    Bellingham, WA
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    the triangle is isosceles with base 8 and height 6. Then you have

    1)
    Tan(T) = (8/2)/6 = 4/6
    T = ArcTan (4/6) = ArcTan (2/3) = approx .588003 radians

    <AED = 2*T = approx 1.17601 radians

    2) length of AE = (4^2+6^2)^(1/2)= 52^(1/2) = approx 7.2111

    3) length of BN = (4^2+12^2)^(1/2) = 160^(1/2) = approx 12.649

    4) length of BE = ((length of BN)^2 + (height of triangle)^2)^(1/2)

    = (160 + 36) ^ (1/2) = 196^(1/2) = exactly 14

    5) Sin(Q) = (6/14)
    Q = ArcSin (6/14) = approx. .442911 radians = <EBN
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