see the picture attached.

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- Dec 7th 2008, 12:09 AMhelloyinganother trigo question
see the picture attached.

- Dec 7th 2008, 12:27 AMMentia
the triangle is isosceles with base 8 and height 6. Then you have

1)

Tan(T) = (8/2)/6 = 4/6

T = ArcTan (4/6) = ArcTan (2/3) = approx .588003 radians

<AED = 2*T = approx 1.17601 radians

2) length of AE = (4^2+6^2)^(1/2)= 52^(1/2) = approx 7.2111

3) length of BN = (4^2+12^2)^(1/2) = 160^(1/2) = approx 12.649

4) length of BE = ((length of BN)^2 + (height of triangle)^2)^(1/2)

= (160 + 36) ^ (1/2) = 196^(1/2) = exactly 14

5) Sin(Q) = (6/14)

Q = ArcSin (6/14) = approx. .442911 radians = <EBN