looks to me that you did everything correct.
the range of is
as I see it, this equation has no solution.
I need help with solving this problem:
arccos x + 2 arcsin (√3/2) = pi/3
I keep getting 1/2, and when I plug it back into the equation it equals pi instead of pi/3. Here's what I did:
arccos x + 2 arcsin (√3/2) = pi/3
arccos x = pi/3 - 2 arcsin (√3/2)
arccos x = -pi/3
x = cos (-pi/3)
x = 1/2
What did I do wrong? What is the correct answer?
I really need help now cuz my math test is Monday! D: