• Dec 6th 2008, 08:24 AM
Crazyheaven
1. cos 3pie/7(cos 2pie/21)+ sin 3pie/7(sin 2pie/21)

2. (tan 73 degrees - tan 13 degrees)/ (1+ tan 73 degrees tan 13 degrees)

Write the expression as a trigonometric function of one number, and then find its exact value.

I'm new to trig and it really confuses me. My book doesn't really give me examples of some of the problems it ask me to solve. Would someone here be willing to work these problem or ones like them to show me step by step how to solve it?

I'm going to be posting quite a few questions within the next couple of days :(.
• Dec 6th 2008, 08:39 AM
running-gag
Quote:

Originally Posted by Crazyheaven
1. cos 3pie/7(cos 2pie/21)+ sin 3pie/7(sin 2pie/21)

Do you mean

$cos(\frac{3 \pi}{7}) cos (\frac{2 \pi}{21}) + sin(\frac{3 \pi}{7}) sin (\frac{2 \pi}{21})$ ?

If so use the formula cos(a-b) = cos(a) cos(b) + sin(a) sin(b)

$cos(\frac{3 \pi}{7}) cos (\frac{2 \pi}{21}) + sin(\frac{3 \pi}{7}) sin (\frac{2 \pi}{21}) = cos(\frac{3 \pi}{7} - \frac{2 \pi}{21}) = cos(\frac{\pi}{3}) = \frac{1}{2}$
• Dec 6th 2008, 08:40 AM
Sean12345
Hi Crazyheaven,

I assume it is supposed to read

$\cos \left(\frac{3\pi}{7}\right)\cdot\cos \left(\frac{2\pi}{21}\right)+\sin \left(\frac{3\pi}{7}\right)\cdot\sin \left(\frac{2\pi}{21}\right)$

A Key point to note is that $\cos(\theta\pm\phi)\equiv\cos\theta\cdot\cos\phi\m p\sin\theta\cdot\sin\phi$

and so the above equation can be written as

$
\cos \left(\frac{3\pi}{7}-\frac{2\pi}{21}\right) = \cos \left(\frac{7\pi}{21}\right) = \cos \left(\frac{\pi}{3}\right)=\frac{1}{2}
$

The second is simlar and uses the identity

$\tan (\theta\pm\phi)\equiv \frac{\tan\theta\pm\tan\phi}{1\mp\tan\theta\cdot\t an\phi}$

Hope this helps.
• Dec 6th 2008, 09:13 AM
Crazyheaven
Wow that helps out a lot. Why couldn't my book break it down like that. How do you make the little pie and times symbol so I can make my problems more clear for now on?
• Dec 6th 2008, 11:07 AM
running-gag
Just quote our posts and you will see how to do !