# Math Help - Re-write the following in their simplest form

1. ## Re-write the following in their simplest form

6sin2(theta)cos2(theta)

2. Originally Posted by dno
6sin2(theta)cos2(theta)
You should know that 2 sin A cos A = sin(2A) ....

3. Originally Posted by mr fantastic
You should know that 2 sin A cos A = sin(2A) ....

yeah I know you've got to use that but I dont know how to apply it to that equation

4. Originally Posted by dno
yeah I know you've got to use that but I dont know how to apply it to that equation
Just to make it clearer:

$\sin{(2n\theta)} = 2\sin{n\theta}\cos{n\theta}$

where n is a real number.

$6\sin{2\theta}\cos{2\theta} = 3\cdot \underbrace{2\sin{2\theta}\cos{2\theta}}_{= ?} = \ldots$