There's this last trig identity... Myself and a friend on the other end of computer keep getting a final answer of 2 ... simply 2. But the Answers say csc^2x
(sin(x-[pi]/2))/(cos([pi]-x))+(tan(x-3[pi]/2))/(-tan([pi]+x))
Have a go at it! Thanks
There's this last trig identity... Myself and a friend on the other end of computer keep getting a final answer of 2 ... simply 2. But the Answers say csc^2x
(sin(x-[pi]/2))/(cos([pi]-x))+(tan(x-3[pi]/2))/(-tan([pi]+x))
Have a go at it! Thanks
It was one of those slip up moments.
Anyways, I got a couple steps further into the solution but after that, it's getting clear that (this is the last question on the homework) this stuff might be one class ahead of us because we haven't reviewed any of the other trig ratios other than sin(-x)=-sin(x) (those 3 ) and sin(pi/2-x)=cos(x) (those 3)
Thanks though. I will haveto complete it after tomorrow's lesson