Any help would be appreciated for these problems. Thanks in advance csc(squared)x-4=0 sec x/2 = cos x/2 2sin(squared)x-cosx=1 3sec(squared)x+4cos(squared)x=7
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Originally Posted by ChargersFan84 2sin(squared)x-cosx=1 You mean 2sin²x-cosx=1 ? In this case just change sin²x by 1-cos²x and solve the second degree equation in cosx
Originally Posted by ChargersFan84 1)csc(squared)x-4=0 2)sec x/2 = cos x/2 3)2sin(squared)x-cosx=1 4)3sec(squared)x+4cos(squared)x=7 1) For what value of x does has or as its value? 2) Can you proceed further? 3) Solve it... 4)Try to do this yourself as number 3 or else i will give further hints...
Last edited by great_math; November 27th 2008 at 08:00 PM.
Just a small mistake in 3) 2 cos²x + cos x - 1 = 0
Awesome. Thanks a bunch! I can take it from there.
Originally Posted by running-gag Just a small mistake in 3) 2 cos²x + cos x - 1 = 0 Sorry... I was asleep at that time..
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