You can now easily find the values of the 4 remaining trigonometric functions.
Substituting this into the expression, we getLet x=3sin(theta), -pi/2<x<pi/2. Simplify the expression: x/square foot of 9 + x squared. (whole bottom is under square root.) I have put 3sin(theta) in for the x and the x squared, is this the right step? I just cannot get the hang of this! Thanks in advance for the help!
Can you take it from here?