1. ## trigonometry

pls see the attactment

2. Since $TA$ and $TB$ are tangent to the circle, then extending the radius to the point of tangency will form right angles with them, i.e. $\angle OAT = \angle OBT = 90^{\circ}$

Now, looking at $\triangle TAB$, we know it is isosceles since $TA = TB$. This implies $\angle TAB = \angle TBA$. Using the fact that the angles of a triangle add up to $180^{\circ}$, you can deduce that $\angle TAB = \angle TBA = 69^{\circ}$

But: \begin{aligned}\angle OAB & = \angle OAT - \angle TAB = 90^{\circ} - 69^{\circ} = 21^{\circ}\\ \angle OBA & = \angle OBT - \angle TBA = 90^{\circ} - 69^{\circ} = 21^{\circ} \end{aligned}

So we have all the required angles to find $AB$ and $TA$. To find $AB$, use the sine law for $\triangle OAB$. Then to find $TA$, use the sine law again for $\triangle TAB$ (you'll need $AB$ first).