# Math Help - Trig Function Simplification

1. ## Trig Function Simplification

I'm trying to simplify the following, using the basic pythagorean identities or other basic trig:

(cos^3 θ + sin^3 θ )/(sin θ + cos θ )

Any help would be appreciated.

2. (cos^3 θ + sin^3 θ )/(sin θ + cos θ )=
=(cos θ + sin θ )*(cos^2 θ - sin θ cos θ + sin^2 θ) / (sin θ + cos θ ) =
=cos^2 θ - sin θ cos θ + sin^2 θ = 1-sinθ cos θ =1-(1/2) sin2θ

3. Nice! Thank you. So did you factor (cos θ + sin θ) out of the denominator?
How did you go about doing that?

4. a^3+b^3=(a+b)(a^2-ab+b^2)