Hi,
Hint : .
Hello guys!
I have a problem solving this equation. I really dont know how to start Could someone pls help me with this...
The problem is that Find all solutions of the given equation in the indicated interval.
3sin2X+cosX = 0 [-pi/2, pi/2]
Thanks in advanced.
ok then I get cosX (6sinX) = 0
Therefore Cos X = 0 where in Cos can only be zero at x equal to pi/2 and -pi/2
Is this right?
How about the 6sinx = 0
Pls check if i did it right....
sin x = 0/6 then sin x = 0
Therefore sin x = 0 wherein sin can only be zero at x equal to 0 and pi.