Thread: trigonometry C3

Solve, for 0 ≤ θ < 360, the equation

2 tan^2 θ + sec θ = 1

giving your answer to 1 decimal place

please help

Hello,

Originally Posted by sharp357

Solve, for 0 ≤ θ < 360, the equation

2 tan^2 θ + sec θ = 1

giving your answer to 1 decimal place

please help

Remember :

$\displaystyle 1+\tan^2(x)=\sec^2(x)$


so your equation is :

$\displaystyle 2\sec^2 \theta+\sec \theta-3=0$

this is a quadratic

ok thaks, i can do this now