I'm stuck on proving a couple trig identities.
Ignore question 1, I got it now.
1.
cos2x / 1 + sin2x = 1 - tanx / 1 + tanx
2.
sin2x / 1 - cos2x = 2csc2x - tanx
Do it exactly the same way as you were shown here: http://www.mathhelpforum.com/math-he...dentities.html
Note that $\displaystyle \frac{1 - \sin (2x)}{\cos (2x)} = \frac{(1 - \sin (2x)) (1 + \sin (2x))}{\cos (2x) (1 + \sin (2x))} = \, ....$