1. ## Trig Word Problem

Please check it to see if it is correct. I got 200.67 from finding the area of the pentagon.

2. 25 is not the height of each triangular face ... it is the vertical height of the pyramid.

the slant height of each face is $s = \sqrt{a^2 + 25^2}$ , where a is the length of the pentagon's apothem.

total surface area, A = area of base + area of faces

$A = \frac{1}{2}ap + \frac{1}{2}sp$

p is the pentagon's perimeter.

3. ## apothem?

How do u find the apothem?

4. $a = \frac{x}{2\tan\left(\frac{\pi}{n}\right)}$

a = apothem
x = side length
n = number of sides for the regular polygon

Perimeter = 5(10.8) = 54

Apothem = s(tan x)/2
= 10.8 (tan 54)/2 = 7.4325

s = sqrt 7.4325^2 + 25^2
= 26.081

A = 1/2 ap + 1/2 sp
= 1/2 (7.4325)(54) + 1/2 (26.081)(54)
= 904.8645