Hi there - I need to Solve 2sin (2θ) = 1 for 0<x<2pi
I've tried this so far:
2sin2x = 1
sin2x = 1/2
2sinxcosx = 1/2
sinxcosx=1/4
sinxcosx - 1/4 = 0
But I don't know how to factor this, if I should be factoring, or how to get all the possible solutions for x... Could someone give me a hand?
- Cam