Hi there - I need to Solve 2sin (2θ) = 1 for 0<x<2pi

I've tried this so far:

2sin2x = 1

sin2x = 1/2

2sinxcosx = 1/2

sinxcosx=1/4

sinxcosx - 1/4 = 0

But I don't know how to factor this, if I should be factoring, or how to get all the possible solutions for x... Could someone give me a hand?

- Cam