I know this might be easy , but I am kinda confused.

Two questions -

1. Sec 37x/6 , what is the exact value

please explain how to do ..

I know you got take 2pi/6 then find what is the greatest multiple. then I dont know what to do!

thank you!

2. Originally Posted by nycpakidemon

I know this might be easy , but I am kinda confused.

Two questions -

1. Sec 37x/6 , what is the exact value

please explain how to do ..

I know you got take 2pi/6 then find what is the greatest multiple. then I dont know what to do!

thank you!
$\displaystyle \sec\left(\frac{37x}{6}\right)$ or $\displaystyle \sec\left(\frac{37\pi}{6}\right)$ ???

$\displaystyle \frac{37\pi}{6} = 6\pi + \frac{\pi}{6}$

so ...

$\displaystyle \sec\left(\frac{37\pi}{6}\right) = \sec\left(\frac{\pi}{6}\right)$

because $\displaystyle \frac{37\pi}{6}$ is coterminal with $\displaystyle \frac{\pi}{6}$.

3. oh bother , im sorry. I meant 37PI/6 , please find the exact value. Use the fact the trigonometric functions are periodic.

4. OH yeah , The answer in the answer sheet is 2(underoot 3) / 3

5. you should know how to find the value of $\displaystyle \sec\left(\frac{\pi}{6}\right)$

it's the reciprocal of $\displaystyle \cos\left(\frac{\pi}{6}\right)$

correct?

7. Originally Posted by nycpakidemon
$\displaystyle \sec \frac{\pi}{6} = \frac{1}{\cos \frac{\pi}{6}}$.
It's expected that you know the value of $\displaystyle \cos \frac{\pi}{6}$.
9. $\displaystyle \cos \frac {\pi}{6}=\frac {\sqrt{3}}{2}$ try remembering the ratios...