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Math Help - Please help !

  1. #1
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    Please help !

    Hey guys im new here , so please help me out.

    I know this might be easy , but I am kinda confused.

    Two questions -

    1. Sec 37x/6 , what is the exact value

    please explain how to do ..

    I know you got take 2pi/6 then find what is the greatest multiple. then I dont know what to do!

    please explain

    thank you!
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  2. #2
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    Quote Originally Posted by nycpakidemon View Post
    Hey guys im new here , so please help me out.

    I know this might be easy , but I am kinda confused.

    Two questions -

    1. Sec 37x/6 , what is the exact value

    please explain how to do ..

    I know you got take 2pi/6 then find what is the greatest multiple. then I dont know what to do!

    please explain

    thank you!
    \sec\left(\frac{37x}{6}\right) or \sec\left(\frac{37\pi}{6}\right) ???



     \frac{37\pi}{6} = 6\pi + \frac{\pi}{6}

    so ...

    \sec\left(\frac{37\pi}{6}\right) = \sec\left(\frac{\pi}{6}\right)

    because \frac{37\pi}{6} is coterminal with \frac{\pi}{6}.
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  3. #3
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    oh bother , im sorry. I meant 37PI/6 , please find the exact value. Use the fact the trigonometric functions are periodic.
    Last edited by mr fantastic; November 27th 2008 at 05:09 PM. Reason: Replaced a word that some members might find slightly offensive
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  4. #4
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    OH yeah , The answer in the answer sheet is 2(underoot 3) / 3
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  5. #5
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    you should know how to find the value of \sec\left(\frac{\pi}{6}\right)

    it's the reciprocal of \cos\left(\frac{\pi}{6}\right)

    correct?
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  6. #6
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    sorry dude i dont know how to find the sec of pi/6 please help!
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  7. #7
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    Quote Originally Posted by nycpakidemon View Post
    sorry dude i dont know how to find the sec of pi/6 please help!
    \sec \frac{\pi}{6} = \frac{1}{\cos \frac{\pi}{6}}.

    It's expected that you know the value of \cos \frac{\pi}{6}.
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  8. #8
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    If i use the calc , I can find tht is is 3pi/2 but how do I find this by an equation....
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  9. #9
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    \cos \frac {\pi}{6}=\frac {\sqrt{3}}{2} try remembering the ratios...

    See this for further help..
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