This one is giving me issues too...
I find the missing side... -sqrt6 + y^2 = -3^2Use the information given about the angle theta, 0 < theta < 2pi, to find the exact value of
(a) sin(2theta) ... etc...
cos theta = - sqrt6/3, pi/2 < theta < pi
-6 + y^2 = -9
y^2 = -3
y = -sqrt3
Then I plug them into the double angle formula... 2 sin theta cos theta.
2 (sqrt3/3)(- sqrt6/3)
Then I get 2( - sqrt18/3)
The answer should be -2 sqrt2/3 ... Did I just make a simple mistake or something?