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Math Help - Sum and Difference

  1. #1
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    Sum and Difference

    <br />
\tan(A + B)={-7/6},<br />
\tan(B)={5/3}<br />

    Find tan(A)
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  2. #2
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    use the sum identity ...

    \tan(a+b) = \frac{\tan{a} + \tan{b}}{1 - \tan{a}\tan{b}}

    sub in what you know, solve for \tan{a}
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  3. #3
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    and how would i solve for tan(a), not sure where to start.
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  4. #4
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    \tan(a+b) = \frac{\tan{a} + \tan{b}}{1 - \tan{a}\tan{b}}

    \tan(a+b) (1 - \tan{a}\tan{b}) = \tan{a} + \tan{b}

    \tan(a+b) - \tan(a+b) \tan{a} \tan{b} = \tan{a} + \tan{b}

    \tan(a+b) - \tan{b} = \tan{a} - \tan(a+b) \tan{a} \tan{b}<br />

    \tan(a+b) - \tan{b} = \tan{a}[1 - \tan(a+b) \tan{b}]

    \frac{\tan(a+b) - \tan{b}}{1 - \tan(a+b) \tan{b}} = \tan{a}
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