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Math Help - Solving Trig Functions?

  1. #1
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    Solving Trig Functions?

    I have a question where I have to solve for the cos, tan, csc, sec, and cot when given a value of sin(theta). One of them is like this:

    sin(theta) = 1/3 0 < theta < pi/2

    Not a clue where to go with this.
    Any help would be appreciated.
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  2. #2
    A riddle wrapped in an enigma
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    Quote Originally Posted by cjh824 View Post
    I have a question where I have to solve for the cos, tan, csc, sec, and cot when given a value of sin(theta). One of them is like this:

    sin(theta) = 1/3 0 < theta < pi/2

    Not a clue where to go with this.
    Any help would be appreciated.
    \sin \theta = \frac{1}{3} \ \ \ \ 0 < \theta < \frac{\pi}{2}

    You are looking for ratios in the 1st quadrant.

    \sin \theta=\frac{y}{r} \ \ \ \ \csc\theta=\frac{r}{y}

    \cos \theta=\frac{x}{r} \ \ \ \ \sec\theta=\frac{r}{x}

    \tan\theta=\frac{y}{x} \ \ \ \ \cot\theta=\frac{x}{y}

    You already know r and y. Use r^2=x^2+y^2 to find x.

    Then, you can find all the other ratios.
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  3. #3
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    Kinda looks familiar to what we were doing in class. Does that mean r^2 - y^2 = x^2?

    Thanks a million too by the way.
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  4. #4
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    Quote Originally Posted by cjh824 View Post
    Kinda looks familiar to what we were doing in class. Does that mean r^2 - y^2 = x^2?

    Thanks a million too by the way.

    That would be correct!
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